$A$ $50 \text{ Hz}$ $AC$ circuit has a $10 \text{ mH}$ inductor and a $2 \text{ } \Omega$ resistor in series. The value of capacitance to be placed in series in the circuit to make the circuit power factor as unity is

  • A
    $1.014 \times 10^{-6} \text{ F}$
  • B
    $1.014 \times 10^{-3} \text{ F}$
  • C
    $2.6 \times 10^{-3} \text{ F}$
  • D
    $4.125 \times 10^{-3} \text{ F}$

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