(B) Given,peak voltage $V_0 = 150 \text{ V}$ and peak current $I_0 = 5 \text{ A}$.Phase difference $\phi = (100 \pi t + \pi) - (100 \pi t + \frac{2 \p

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(B) Given,peak voltage $V_0 = 150 \text{ V}$ and peak current $I_0 = 5 \text{ A}$.Phase difference $\phi = (100 \pi t + \pi) - (100 \pi t + \frac{2 \pi}{3}) = \frac{\pi}{3} = 60^{\circ}$.Average power dissipated $P_{av} = V_{rms} I_{rms} \cos \phi = \frac{V_0}{\sqrt{2}} \cdot \frac{I_0}{\sqrt{2}} \cos 60^{\circ} = \frac{150 \times 5}{2} \times \frac{1}{2} = 187.5 \text{ W}$.Impedance $Z = \frac{V_0}{I_0} = \frac{150}{5} = 30 \Omega$.Since $\cos \phi = \frac{R}{Z}$,we have $R = Z \cos 60^{\circ} = 30 \times 0.5 = 15 \Omega$.

Class 12 Physics Alternating Current RL, RC and LC AC Circuits

Medium

$A$ resistor and an inductor are connected in series to an $AC$ source of voltage $V = 150 \sin (100 \pi t + \pi) \text{ V}$. If the current in the circuit is $I = 5 \sin (100 \pi t + \frac{2 \pi}{3}) \text{ A}$,then the average power dissipated and the resistance of the resistor are respectively:

AP EAMCET 2018 All AP EAMCET

A
$187.5 \text{ W}, 30 \Omega$
B
$187.5 \text{ W}, 15 \Omega$
C
$375 \text{ W}, 30 \Omega$
D
$375 \text{ W}, 15 \Omega$

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Alternating Current

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RL, RC and LC AC Circuits

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AP EAMCET 2018 Paper All AP EAMCET years →

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$(iii)$ Voltage across capacitor.

Easy

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EasyAP EAMCET 2024

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MediumMHT CET 2025

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An alternating emf is applied across a parallel combination of a resistance $R$,capacitance $C$ and an inductance $L$. If $I_R$,$I_L$,and $I_C$ are the currents through $R$,$L$,and $C$ respectively,then the diagram which correctly represents the phase relationship among $I_R$,$I_L$,$I_C$,and the source emf $E$ is:

Medium

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$A$ resistor and an inductor are connected in series to an $AC$ source of voltage $V = 150 \sin (100 \pi t + \pi) \text{ V}$. If the current in the circuit is $I = 5 \sin (100 \pi t + \frac{2 \pi}{3}) \text{ A}$,then the average power dissipated and the resistance of the resistor are respectively:

Similar Questions

If $i$ is the current in an $L-C-R$ series $AC$ circuit,what are the formulas for:$(i)$ Voltage across resistance.$(ii)$ Voltage across inductor.$(iii)$ Voltage across capacitor.

In the figure,if $A$ and $B$ are identical bulbs,which bulb glows brighter?

The power factor of a $CR$ circuit is $\frac{1}{\sqrt{2}}$. If the frequency of an $AC$ signal is halved,then the power factor of the circuit will become:

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If $i$ is the current in an $L-C-R$ series $AC$ circuit,what are the formulas for:
$(i)$ Voltage across resistance.
$(ii)$ Voltage across inductor.
$(iii)$ Voltage across capacitor.