A rightarrow P is a first order reaction. The | vedclass

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(B) For a reaction $A \rightarrow P$,the rate of reaction is defined as the negative of the rate of change of concentration of reactant $A$ with respe

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$m$

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(B) For a reaction $A ightarrow P$,the rate of reaction is defined as the negative of the rate of change of concentration of reactant $A$ with respect to time,i.e.,$r_{	ext{inst}} = -\frac{d[A]}{dt}$.In the given graph,the $y$-axis represents the concentration of $A$ and the $x$-axis represents time.The slope of the tangent drawn to the curve at any point $C$ is given by $\frac{d[A]}{dt}$.Since the curve shows a decrease in concentration with time,the slope $\frac{d[A]}{dt}$ is negative.Therefore,the instantaneous rate of reaction at point $C$ is equal to the negative of the slope,which is $-(	ext{slope})$.However,in the context of the provided options and the standard interpretation of such graphical problems where $m$ represents the magnitude of the slope (i.e.,$m = |	ext{slope}|$),the instantaneous rate is equal to $m$.

Time $(s)$	$0$	$100$	$200$	$300$	$400$	$700$	$800$
$[C_4H_9Cl]$ $(mol \, L^{-1})$	$0.100$	$0.082$	$0.067$	$0.055$	$0.044$	$0.021$	$0.017$

$A \rightarrow P$ is a first order reaction. The following graph is obtained for this reaction,($x$-axis $=$ time; $y$-axis $=$ concentration of $A$). The instantaneous rate of the reaction at point $C$ is

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