$A$ metal rod $AB$ of length $50 \text{ cm}$ is moving at a velocity $8 \text{ ms}^{-1}$ in a magnetic field of $2 \text{ T}$. If the field is at $60^{\circ}$ with the plane of motion as shown in the figure,then the potentials $V_A$ and $V_B$ are related by

  • A
    $V_A-V_B=8 \text{ V}$
  • B
    $V_A-V_B=4 \text{ V}$
  • C
    $V_B-V_A=8 \text{ V}$
  • D
    $V_B-V_A=4 \text{ V}$

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