A coil of wire of radius r has 600 turns and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The self-inductance $L$ of a circular coil is given by $L = \frac{N \Phi_B}{I}$.For a circular coil,the magnetic field at the center is $B = \frac

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(B) The self-inductance $L$ of a circular coil is given by $L = \frac{N \Phi_B}{I}$.For a circular coil,the magnetic field at the center is $B = \frac{\mu_0 N I}{2r}$.The magnetic flux through the coil is $\Phi_B = B \cdot A = \left( \frac{\mu_0 N I}{2r} ight) (\pi r^2) = \frac{\mu_0 N I \pi r}{2}$.Thus,$L = \frac{N}{I} \left( \frac{\mu_0 N I \pi r}{2} ight) = \frac{\mu_0 \pi r}{2} N^2$.This shows that $L \propto N^2$.Therefore,$\frac{L_2}{L_1} = \left( \frac{N_2}{N_1} ight)^2$.Given $L_1 = 108 \ mH$,$N_1 = 600$,and $N_2 = 500$:$L_2 = L_1 \left( \frac{N_2}{N_1} ight)^2 = 108 	imes \left( \frac{500}{600} ight)^2 = 108 	imes \left( \frac{5}{6} ight)^2 = 108 	imes \frac{25}{36} = 3 	imes 25 = 75 \ mH$.

$A$ coil of wire of radius $r$ has $600$ turns and self-inductance of $108 \ mH$. The self-inductance of a coil with the same radius and $500$ turns is (in $mH$)

Similar Questions

Current in a coil changes from $4 \,A$ to zero in $0.1 \,s$ and the emf induced is $100 \,V$. The self inductance of the coil is (in $\,H$)

The current in a coil changes from $4 \, A$ to $0 \, A$ in $0.1 \, s$. If the average induced $e.m.f.$ is $100 \, V$,what is the self-inductance of the coil in $H$?

$A$ long solenoid has $1500$ turns. When a current of $3.5 \, A$ flows through it, the magnetic flux linked with each turn of the solenoid is $2.8 \times 10^{-3} \, Wb$. The self-inductance of the solenoid is (in $ \, H$)

Self-induction of a solenoid cannot be increased by

The unit of self-inductance of a coil is

Vedclass Test Series

Exam Paper Generator

Online Exam Module