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(C) The magnetic field $B$ at the center of a solenoid is given by $B = \mu_0 (N/l) I$,where $N$ is the number of turns,$l$ is the length,and $I$ is t

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increasing the current through it

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(C) The magnetic field $B$ at the center of a solenoid is given by $B = \mu_0 (N/l) I$,where $N$ is the number of turns,$l$ is the length,and $I$ is the current.Total magnetic flux $\phi$ linked with the solenoid is $\phi = B A N = \mu_0 (N^2/l) A I$,where $A$ is the cross-sectional area.By the definition of self-induction,$\phi = L I$.Comparing the two expressions,the self-inductance $L$ is given by $L = \frac{\mu_0 N^2 A}{l}$.From this formula,it is clear that $L$ depends on the number of turns $N$,cross-sectional area $A$,and length $l$,but it is independent of the current $I$ flowing through the solenoid.

Self-induction of a solenoid cannot be increased by

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