A uniformly charged conducting sphere of 2.4 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Diameter of the sphere $d = 2.4 \, m$. Radius of the sphere $r = \frac{d}{2} = 1.2 \, m$. Surface charge density $\sigma = 80.0 \, \mu C m^

Vedclass · Accepted Answer

$1.45 	imes 10^{-3} \, C$

Vedclass · Answer

(B) Given: Diameter of the sphere $d = 2.4 \, m$. Radius of the sphere $r = \frac{d}{2} = 1.2 \, m$. Surface charge density $\sigma = 80.0 \, \mu C m^{-2} = 80 	imes 10^{-6} \, C m^{-2}$. The total charge $Q$ on the surface of the sphere is given by the product of surface charge density and surface area $A$. $Q = \sigma 	imes A = \sigma 	imes (4 \pi r^2)$. Substituting the values: $Q = 80 	imes 10^{-6} 	imes 4 	imes 3.14159 	imes (1.2)^2$. $Q = 80 	imes 10^{-6} 	imes 4 	imes 3.14159 	imes 1.44$. $Q \approx 1.4476 	imes 10^{-3} \, C$. Rounding to the nearest value, $Q \approx 1.45 	imes 10^{-3} \, C$.

$A$ uniformly charged conducting sphere of $2.4 \, m$ diameter has a surface charge density of $80.0 \, \mu C m^{-2}$. The charge on the sphere is nearly

Similar Questions

$A$ spherical conducting shell of inner radius $r_1$ and outer radius $r_2$ has a net charge $Q$. $A$ point charge $-q$ is placed at the center of the shell. Determine the surface charge density on the inner and outer surfaces of the shell.

Write an equation for the electric potential due to a linear charge distribution.

If a solid and a hollow conducting sphere have the same radius, then:

If a metal cube of side $5 \, cm$ has a charge of $6 \, \mu C$,then the surface charge density is

Three concentric metallic spherical shells of radii $R, 2R, 3R$ are given charges $Q_1, Q_2, Q_3$ respectively. It is found that the surface charge densities on the outer surfaces of the shells are equal. Then,the ratio of the charges given to the shells,$Q_1 : Q_2 : Q_3$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module