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(C) Given: Mass $m = 5 \ kg$,initial velocity $\vec{u} = (30 \hat{i} + 40 \hat{j}) \ m/s$,and force $\vec{F} = -(\hat{i} + 5 \hat{j}) \ N$.Using Newto

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$40$

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(C) Given: Mass $m = 5 \ kg$,initial velocity $\vec{u} = (30 \hat{i} + 40 \hat{j}) \ m/s$,and force $\vec{F} = -(\hat{i} + 5 \hat{j}) \ N$.Using Newton's second law,the acceleration $\vec{a}$ is given by $\vec{a} = \frac{\vec{F}}{m} = \frac{-(\hat{i} + 5 \hat{j})}{5} = (-0.2 \hat{i} - 1 \hat{j}) \ m/s^2$.The velocity at any time $t$ is given by $\vec{v} = \vec{u} + \vec{a}t$.Substituting the components,the $y$-component of velocity is $v_y = u_y + a_y t$.Here,$u_y = 40 \ m/s$ and $a_y = -1 \ m/s^2$.We want the time $t$ when $v_y = 0$.$0 = 40 + (-1)t$.$t = 40 \ s$.

$A$ body of mass $5 \ kg$ starts from the origin with an initial velocity $(30 \hat{i} + 40 \hat{j}) \ m/s$. If a constant force $-(\hat{i} + 5 \hat{j}) \ N$ acts on the body,then the time in which the $y$-component of its velocity becomes zero is (in $s$)

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