A cyclotron's oscillator frequency is 20 MHz. | vedclass

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(D) The cyclotron frequency is given by the formula $f = \frac{qB}{2\pi m}$.Rearranging the formula to solve for the magnetic field $B$,we get $B = \f

Vedclass · Accepted Answer

$1.31$

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(D) The cyclotron frequency is given by the formula $f = \frac{qB}{2\pi m}$.Rearranging the formula to solve for the magnetic field $B$,we get $B = \frac{2\pi mf}{q}$.Given values are:Frequency $f = 20 MHz = 20 	imes 10^6 Hz$Charge of proton $q = 1.6 	imes 10^{-19} C$Mass of proton $m = 1.67 	imes 10^{-27} kg$Substituting these values into the formula:$B = \frac{2 	imes 3.14 	imes 1.67 	imes 10^{-27} 	imes 20 	imes 10^6}{1.6 	imes 10^{-19}}$$B = \frac{209.536 	imes 10^{-21}}{1.6 	imes 10^{-19}}$$B \approx 1.31 T$.

$A$ cyclotron's oscillator frequency is $20 MHz$. The operating magnetic field for accelerating protons is (charge of proton $= 1.6 \times 10^{-19} C$,mass of proton $= 1.67 \times 10^{-27} kg$). (in $T$)

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