$S = \{z \in \mathbb{C} : |z + 1 - i| = 1\}$ represents
- Athe circle with centre at $(-1, 1)$ and radius $1$ unit
- Bthe circle with centre at $(1, -1)$ and radius $1$ unit
- Cthe closed circular disc with centre at $(1, -1)$ and radius $1$ unit
- Dthe closed circular disc with centre at $(-1, 1)$ and radius $1$ unit
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View SolutionLet $S = \{z \in \mathbb{C} : \left|\frac{z-6i}{z-2i}\right| = 1 \text{ and } \left|\frac{z-8+2i}{z+2i}\right| = \frac{3}{5}\}$. Then $\sum_{z \in S} |z|^2$ is equal to
DifficultJEE MAIN 2026
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