$A$ gun and a target are at the same horizontal level separated by a distance of $600 \,m$. The bullet is fired from the gun with a velocity of $500 \,ms^{-1}$. In order to hit the target, the gun should be aimed to a height $h$ above the target. The value of $h$ is (Acceleration due to gravity, $g=10 \,ms^{-2}$) (in $\,m$)
- A$2.4$
- B$3.6$
- C$7.2$
- D$10.8$
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Similar Questions
$A$ body is projected horizontally from the top of a tower of height $180 \,m$ with a velocity of $20 \,ms^{-1}$. If acceleration due to gravity is $10 \,ms^{-2}$, then match the following:
$A$. Velocity of the body after $1 \,s$ (in $ms^{-1}$)
$I$. $5$
$B$. Horizontal displacement of the body after $1 \,s$ (in $m$)
$II$. $20$
$C$. Vertical displacement of the body after $1 \,s$ (in $m$)
$III$. $10$
$D$. Vertical velocity of the body after $1 \,s$ (in $ms^{-1}$)
$IV$. $22.4$
| $A$. Velocity of the body after $1 \,s$ (in $ms^{-1}$) | $I$. $5$ |
| $B$. Horizontal displacement of the body after $1 \,s$ (in $m$) | $II$. $20$ |
| $C$. Vertical displacement of the body after $1 \,s$ (in $m$) | $III$. $10$ |
| $D$. Vertical velocity of the body after $1 \,s$ (in $ms^{-1}$) | $IV$. $22.4$ |
Two projectiles,one fired from the surface of the Earth with velocity $10 \, m/s$ and the other fired from the surface of another planet with initial speed $5 \, m/s$,trace identical trajectories. The value of the acceleration due to gravity on the planet is ......... $m/s^2$.
Medium
View Solution$A$ particle is thrown with a speed of $12 \, m/s$ at an angle $60^o$ with the horizontal. The time interval between the moments when its speed is $10 \, m/s$ is $(g = 10 \, m/s^2)$.........$s$
Difficult
View SolutionWhen a ball is thrown with a velocity of $50 \ m s^{-1}$ at an angle $30^{\circ}$ with the horizontal,it remains in the air for how many seconds? (Take $g = 10 \ m s^{-2}$)
$A$ shell is fired at an angle of $30^{\circ}$ to the horizontal with a velocity of $196 \,m/s$. What is the time of flight (in $\,s$)? (Take $g = 9.8 \,m/s^2$)
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