frac{1-cos(2x)+sin(x)}{sin(2x)+cos(x)} = | vedclass

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Question

(C) આપેલ પદાવલિ: $\frac{1-\cos(2x)+\sin(x)}{\sin(2x)+\cos(x)}$નિત્યસમ $\cos(2x) = 1 - 2\sin^2(x)$ નો ઉપયોગ કરતા,અંશ: $1 - (1 - 2\sin^2(x)) + \sin(x) =

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$	an(x)$

Vedclass · Answer

(C) આપેલ પદાવલિ: $\frac{1-\cos(2x)+\sin(x)}{\sin(2x)+\cos(x)}$નિત્યસમ $\cos(2x) = 1 - 2\sin^2(x)$ નો ઉપયોગ કરતા,અંશ: $1 - (1 - 2\sin^2(x)) + \sin(x) = 2\sin^2(x) + \sin(x) = \sin(x)(2\sin(x) + 1)$નિત્યસમ $\sin(2x) = 2\sin(x)\cos(x)$ નો ઉપયોગ કરતા,છેદ: $2\sin(x)\cos(x) + \cos(x) = \cos(x)(2\sin(x) + 1)$આ કિંમતો પદાવલિમાં મુકતા: $\frac{\sin(x)(2\sin(x) + 1)}{\cos(x)(2\sin(x) + 1)} = \frac{\sin(x)}{\cos(x)} = 	an(x)$

$\frac{1-\cos(2x)+\sin(x)}{\sin(2x)+\cos(x)} = $

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