A ray of light passing through the point (2, | vedclass

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(C) Let the point $P$ be $(0, b)$ since it lies on the $Y$-axis. Thus,$a = 0$.By the law of reflection,the angle of incidence equals the angle of refl

Vedclass · Accepted Answer

$a + 13$

Vedclass · Answer

(C) Let the point $P$ be $(0, b)$ since it lies on the $Y$-axis. Thus,$a = 0$.By the law of reflection,the angle of incidence equals the angle of reflection. This is equivalent to saying that the image of the point $(2, 3)$ with respect to the $Y$-axis,which is $(-2, 3)$,lies on the line containing the reflected ray.The reflected ray passes through $P(0, b)$ and $(3, 2)$.The equation of the line passing through $(-2, 3)$ and $(3, 2)$ is given by:$y - 3 = \frac{2 - 3}{3 - (-2)} (x - (-2))$$y - 3 = \frac{-1}{5} (x + 2)$$5y - 15 = -x - 2$$x + 5y = 13$Since $P(0, b)$ lies on this line,we substitute $x = 0$ and $y = b$:$0 + 5b = 13$$5b = 13$Since $a = 0$,we can write $13 = a + 13$.Therefore,$5b = a + 13$.

$A$ ray of light passing through the point $(2, 3)$ reflects on the $Y$-axis at a point $P$. If the reflected ray passes through the point $(3, 2)$ and $P = (a, b)$,then $5b =$

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