lim _{x rightarrow 0} left( frac{sin ax}{tan | vedclass

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Question

(B) We know that $\lim _{x ightarrow 0} \frac{\sin kx}{kx} = 1$ and $\lim _{x ightarrow 0} \frac{	an kx}{kx} = 1$. $\lim _{x ightarrow 0} \left

Vedclass · Accepted Answer

$\frac{a}{b}$

Vedclass · Answer

(B) We know that $\lim _{x ightarrow 0} \frac{\sin kx}{kx} = 1$ and $\lim _{x ightarrow 0} \frac{	an kx}{kx} = 1$. $\lim _{x ightarrow 0} \left( \frac{\sin ax}{	an bx} ight) = \lim _{x ightarrow 0} \left( \frac{\sin ax}{ax} \cdot ax \cdot \frac{bx}{	an bx} \cdot \frac{1}{bx} ight)$ $= \lim _{x ightarrow 0} \left( \frac{\sin ax}{ax} ight) \cdot \lim _{x ightarrow 0} \left( \frac{bx}{	an bx} ight) \cdot \lim _{x ightarrow 0} \left( \frac{ax}{bx} ight)$ $= 1 \cdot 1 \cdot \frac{a}{b} = \frac{a}{b}$.

$\lim _{x \rightarrow 0} \left( \frac{\sin ax}{\tan bx} \right)$ is equal to

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