$\left[\begin{array}{ccc} 1 & 2 & 3 \\ -1 & 1 & 2 \\ 3 & 0 & 2 \end{array}\right]^{\left|\begin{array}{cc} 2022 & 2024 \\ 2021 & 2023 \end{array}\right|}$ is equal to

  • A
    $\left[\begin{array}{ccc} 8 & 4 & 11 \\ 4 & -1 & 3 \\ 9 & 6 & 13 \end{array}\right]$
  • B
    $\left[\begin{array}{ccc} 8 & 4 & 13 \\ 4 & -1 & 3 \\ 9 & 6 & 12 \end{array}\right]$
  • C
    $\left[\begin{array}{ccc} 8 & 4 & 13 \\ 4 & -1 & 3 \\ 9 & 6 & 13 \end{array}\right]$
  • D
    $\left[\begin{array}{ccc} 8 & 4 & 11 \\ 4 & 1 & 13 \\ 9 & 6 & 13 \end{array}\right]$

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If $A = \begin{bmatrix} 2 & 3 \\ 0 & -1 \end{bmatrix}$,then the value of $\det(A^4) + \det(A^{10} - (\operatorname{adj}(2A))^{10})$ is equal to ........

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$\left|\begin{array}{lll}2 & 3 & 5 \\ 3 & 5 & 2 \\ 5 & 2 & 3\end{array}\right|+\left|\begin{array}{ccc}1 & 1 & 1 \\ 7 & 11 & 13 \\ 49 & 121 & 169\end{array}\right|=$

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