$f: R \rightarrow R$ is defined by $f(x+y)=f(x)+12y, \forall x, y \in R$. If $f(1)=6$,then $\sum_{r=1}^n f(r)=$

  • A
    $n^2$
  • B
    $5n^2$
  • C
    $6n^2$
  • D
    $\frac{3n(n+1)}{2}$

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