A microscope consists of an objective of foca | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For the eyepiece,the image distance $v_e = -25 \ cm$ and focal length $f_e = 5 \ cm$. Using the lens formula $\frac{1}{v_e} - \frac{1}{u_e} = \fra

Vedclass · Accepted Answer

$2.7$

Vedclass · Answer

(B) For the eyepiece,the image distance $v_e = -25 \ cm$ and focal length $f_e = 5 \ cm$. Using the lens formula $\frac{1}{v_e} - \frac{1}{u_e} = \frac{1}{f_e}$:$\frac{1}{-25} - \frac{1}{u_e} = \frac{1}{5} \Rightarrow \frac{1}{u_e} = -\frac{1}{25} - \frac{1}{5} = -\frac{6}{25} \Rightarrow u_e = -\frac{25}{6} \ cm$.The distance of the image formed by the objective from the objective is $v_0 = L - |u_e| = 10.5 - \frac{25}{6} = \frac{63-25}{6} = \frac{38}{6} \ cm$.For the objective,$f_0 = 1.9 \ cm$ and $v_0 = \frac{38}{6} \ cm$. Using the lens formula $\frac{1}{v_0} - \frac{1}{u_0} = \frac{1}{f_0}$:$\frac{1}{38/6} - \frac{1}{u_0} = \frac{1}{1.9} \Rightarrow \frac{6}{38} - \frac{1}{u_0} = \frac{10}{19} \Rightarrow \frac{3}{19} - \frac{10}{19} = \frac{1}{u_0}$.$\frac{1}{u_0} = -\frac{7}{19} \Rightarrow u_0 = -\frac{19}{7} \approx -2.71 \ cm$.Thus,the object should be placed at a distance of $2.7 \ cm$ from the objective.

Similar Questions

Two rods of the same length and material transfer a given amount of heat in $12 \, s$,when they are joined in parallel. But when they are joined in series,then they will transfer the same amount of heat under the same conditions in ......... $s$.

Two vibrating tuning forks produce progressive waves given by $Y_1 = 4 \sin(500 \pi t)$ and $Y_2 = 2 \sin(506 \pi t)$. The number of beats produced per minute is:

$A$ sufficiently long closed organ pipe has a small hole at its bottom. Initially,the pipe is empty. Water is poured into the pipe at a constant rate. The fundamental frequency of the air column in the pipe:

Which of the following is paramagnetic?

In which of the following is the renal portal system found?

Vedclass Test Series

Exam Paper Generator

Online Exam Module