$a, b, c$ are non-coplanar vectors. If $a+3 b+4 c=x(a-2 b+3 c)+y(a+5 b-2 c)+z(6 a+14 b+4 c)$,then $x+y+z=$

  • A
    $-5$
  • B
    $-4$
  • C
    $4$
  • D
    $5$

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