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(D) For a binomial distribution $B(n, p)$,the variance is given by $\operatorname{Var}(X) = npq$,where $q = 1 - p$.Given $n = 15$ and $\operatorname{V

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$0.3, 0.7$

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(D) For a binomial distribution $B(n, p)$,the variance is given by $\operatorname{Var}(X) = npq$,where $q = 1 - p$.Given $n = 15$ and $\operatorname{Var}(X) = 3.15$.Substituting the values,we get $15 	imes p(1 - p) = 3.15$.Dividing by $15$,we get $p(1 - p) = \frac{3.15}{15} = 0.21$.This simplifies to $p - p^2 = 0.21$,or $p^2 - p + 0.21 = 0$.Solving the quadratic equation using the factorization method:$p^2 - 0.7p - 0.3p + 0.21 = 0$$p(p - 0.7) - 0.3(p - 0.7) = 0$$(p - 0.7)(p - 0.3) = 0$.Thus,the possible values for $p$ are $0.7$ and $0.3$.

$A$ discrete random variable $X$ has the distribution $B(15, p)$. Given that $\operatorname{Var}(X) = 3.15$. Then,the two possible values of $p$ are

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