A metallic solid undergoes Frenkel defect. It | vedclass

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(A) In a Frenkel defect,an ion leaves its lattice site and occupies an interstitial site within the same crystal lattice. Since no atoms or ions are l

Vedclass · Accepted Answer

$M=M_0, V=V_0, D=D_0$

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(A) In a Frenkel defect,an ion leaves its lattice site and occupies an interstitial site within the same crystal lattice. Since no atoms or ions are lost from or added to the crystal,the total mass $(M)$ remains constant $(M = M_0)$. The volume $(V)$ of the crystal remains unchanged because the lattice structure does not expand or contract significantly $(V = V_0)$. Since density $(D)$ is defined as mass divided by volume $(D = M/V)$,and both mass and volume remain constant,the density remains unchanged $(D = D_0)$. Therefore,the correct option is $(A)$.

$A$ metallic solid undergoes Frenkel defect. Its original mass,volume and density are $M_0$,$V_0$ and $D_0$ respectively. After Frenkel defect the mass,volume and density are $M$,$V$ and $D$ respectively. The variations of $M$,$V$ and $D$ after Frenkel defect are

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