(A) Given initial conditions: $V_1 = 10 \,L$,$T_1 = 27^{\circ} C = 300 \,K$,$p_1 = 12 \,atm$.Final conditions: $V_2 = 6 \,L$,$T_2 = (27 + 30)^{\circ}

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(A) Given initial conditions: $V_1 = 10 \,L$,$T_1 = 27^{\circ} C = 300 \,K$,$p_1 = 12 \,atm$.Final conditions: $V_2 = 6 \,L$,$T_2 = (27 + 30)^{\circ} C = 57^{\circ} C = 330 \,K$.Using the ideal gas law,$\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$.Rearranging for $p_2$: $p_2 = \frac{p_1 V_1 T_2}{T_1 V_2}$.Substituting the values: $p_2 = \frac{12 \times 10 \times 330}{300 \times 6}$.$p_2 = \frac{120 \times 330}{1800} = \frac{39600}{1800} = 22 \,atm$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Easy

$A$ container of $10 \,L$ is filled with an ideal gas at a temperature of $27^{\circ} C$ at a pressure of $12 \,atm$. The volume of the container is reduced to $6 \,L$ and the temperature of the gas is increased by $30^{\circ} C$. What is the final pressure of the gas (in $\,atm$)?

AP EAMCET 2022 All AP EAMCET

A
$22$
B
$20$
C
$11$
D
$9$

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Kinetic Theory of Gases

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Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

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$A$ container of $10 \,L$ is filled with an ideal gas at a temperature of $27^{\circ} C$ at a pressure of $12 \,atm$. The volume of the container is reduced to $6 \,L$ and the temperature of the gas is increased by $30^{\circ} C$. What is the final pressure of the gas (in $\,atm$)?

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