E, m, L, G represent energy,mass,angular mome | vedclass

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(A) The dimensions of the given physical quantities are:$E = [M L^2 T^{-2}]$$m = [M]$$L = [M L^2 T^{-1}]$$G = [M^{-1} L^3 T^{-2}]$Substituting these i

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(A) The dimensions of the given physical quantities are:$E = [M L^2 T^{-2}]$$m = [M]$$L = [M L^2 T^{-1}]$$G = [M^{-1} L^3 T^{-2}]$Substituting these into the expression $\frac{E L^2}{m^5 G^2}$:$\left[\frac{E L^2}{m^5 G^2}ight] = \frac{[M L^2 T^{-2}] [M L^2 T^{-1}]^2}{[M]^5 [M^{-1} L^3 T^{-2}]^2}$$= \frac{[M L^2 T^{-2}] [M^2 L^4 T^{-2}]}{[M^5] [M^{-2} L^6 T^{-4}]}$$= \frac{[M^3 L^6 T^{-4}]}{[M^3 L^6 T^{-4}]}$$= [M^0 L^0 T^0]$Since the dimensions are $[M^0 L^0 T^0]$,the quantity is dimensionless,which corresponds to the dimensions of an $	ext{Angle}$.

$E, m, L, G$ represent energy,mass,angular momentum,and gravitational constant respectively. The dimensions of $\frac{EL^2}{m^5 G^2}$ will be that of

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