$1 \text{ amu}$ is equal to

  • A
    $931 \text{ keV}$
  • B
    $931 \text{ eV}$
  • C
    $931 \text{ MeV}$
  • D
    $9.31 \text{ MeV}$

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${ }_{92}^{238} A \rightarrow{ }_{90}^{234} B +{ }_2^4 D + Q$
In the given nuclear reaction,the approximate amount of energy released will be $.....\,MeV$.
[Given: mass of ${ }_{92}^{238} A = 238.05079 \, u$,mass of ${ }_{90}^{234} B = 234.04363 \, u$,mass of ${ }_2^4 D = 4.00260 \, u$,and $1 \, u = 931.5 \, MeV/c^2$]

What is nuclear energy? Explain how nuclear energy is released from the curve of binding energy.

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