A train of mass 10^6 kg is moving at a const | vedclass

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(B) Given: Mass of the train $m = 10^6 \ kg$,Speed $v = 108 \ km/h$. First,convert the speed into $SI$ units: $v = 108 	imes \frac{5}{18} \ m/s = 30

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(B) Given: Mass of the train $m = 10^6 \ kg$,Speed $v = 108 \ km/h$. First,convert the speed into $SI$ units: $v = 108 	imes \frac{5}{18} \ m/s = 30 \ m/s$. The frictional force per $100 \ kg$ is $0.5 \ N$. Total frictional force $F = \frac{10^6 \ kg}{100 \ kg} 	imes 0.5 \ N = 10^4 	imes 0.5 \ N = 5000 \ N$. Since the train is moving at a constant speed,the driving force must be equal to the frictional force: $F_{drive} = F = 5000 \ N$. Power $P = F_{drive} 	imes v = 5000 \ N 	imes 30 \ m/s = 150,000 \ W = 150 \ kW$.

$A$ train of mass $10^6 \ kg$ is moving at a constant speed of $108 \ km/h$. If the frictional force acting on it is $0.5 \ N$ per $100 \ kg$,then the power of the train is (in $kW$)

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