A tube-well pumps out 2400 ; kg of water per | vedclass

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(C) Mass of water pumped per minute = $2400 \; kg$. Mass of water pumped per second $(m)$ = $\frac{2400}{60} = 40 \; kg/s$. Velocity of water $(v)$ =

Vedclass · Accepted Answer

$6.48 	imes 10^6 \; J$

Vedclass · Answer

(C) Mass of water pumped per minute = $2400 \; kg$. Mass of water pumped per second $(m)$ = $\frac{2400}{60} = 40 \; kg/s$. Velocity of water $(v)$ = $3 \; m/s$. Kinetic energy per second (Power) = $\frac{1}{2} m v^2 = \frac{1}{2} 	imes 40 	imes (3)^2 = 20 	imes 9 = 180 \; W$ (or $J/s$). Total time $(t)$ = $10 \; hours = 10 	imes 3600 = 36000 \; s$. Total work done = $	ext{Power} 	imes 	ext{Time} = 180 	imes 36000 = 6,480,000 \; J = 6.48 	imes 10^6 \; J$.

$A$ tube-well pumps out $2400 \; kg$ of water per minute. If water is coming out with a velocity of $3 \; m/s$, how much work is done if the pump runs for $10 \; hours$?

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