(C) Resistance of galvanometer,$G = 50 \Omega$. Full scale current,$i_g = 0.05 \text{ A}$. Maximum current to be measured,$i = 5 \text{ A}$. Area of c

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Resistance of galvanometer,$G = 50 \Omega$. Full scale current,$i_g = 0.05 \text{ A}$. Maximum current to be measured,$i = 5 \text{ A}$. Area of cross-section,$A = 2.97 \times 10^{-2} \text{ cm}^2 = 2.97 \times 10^{-6} \text{ m}^2$. Specific resistance,$\rho = 5 \times 10^{-7} \Omega\text{-m}$. To convert a galvanometer into an ammeter,a shunt resistance $S$ is connected in parallel. $S = \frac{i_g G}{i - i_g} = \frac{0.05 \times 50}{5 - 0.05} = \frac{2.5}{4.95} = \frac{250}{495} = \frac{50}{99} \Omega$. Using the formula for resistance,$S = \rho \frac{l}{A}$,we get $l = \frac{S \cdot A}{\rho}$. $l = \frac{50}{99} \times \frac{2.97 \times 10^{-6}}{5 \times 10^{-7}} = \frac{50}{99} \times \frac{29.7}{5} = 10 \times 0.3 = 3 \text{ m}$.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Difficult

$A$ galvanometer,having a resistance of $50 \Omega$,gives a full scale deflection for a current of $0.05 \text{ A}$. The length in metre of a resistance wire of area of cross-section $2.97 \times 10^{-2} \text{ cm}^2$ that can be used to convert the galvanometer into an ammeter which can read a maximum of $5 \text{ A}$ current is: (Specific resistance of the wire $= 5 \times 10^{-7} \Omega\text{-m}$)

TS EAMCET 2003 All TS EAMCET

AP EAMCET 2003 All AP EAMCET

A
$9$
B
$6$
C
$3$
D
$1.5$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Moving Charges and Magnetism

Subtopic

The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Previous Year

TS EAMCET 2003 Paper All TS EAMCET years →

Previous Year

AP EAMCET 2003 Paper All AP EAMCET years →

The coil of a moving coil galvanometer has an effective area of $4 \times 10^{-2} \, m^2$. It is suspended in a magnetic field of $5 \times 10^{-2} \, Wb \, m^{-2}$. If the deflection in the galvanometer coil is $0.2 \, rad$, when a current of $5 \, mA$ is passed through it, then

MediumAP EAMCET 2021

View Solution

$A$ galvanometer has a resistance of $25 \, \Omega$ and a maximum of $0.01 \, A$ current can be passed through it. In order to change it into an ammeter of range $10 \, A$, the shunt resistance required is

Medium

View Solution

The deflection in a moving coil galvanometer of resistance $45 \Omega$ falls from $30$ divisions to $3$ divisions. The length of the shunt wire required to convert the galvanometer into an ammeter is [specific resistance of the material of the shunt wire $= 5 \times 10^{-7} \Omega m$ and area of cross-section of the wire $= 4 \times 10^{-7} m^2$]. (in $m$)

MediumMHT CET 2020

View Solution

Match the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:

List-$I$ List-$II$

$A$. Figure of merit $(k)$ $P$. in series

$B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized

$C$. Deflection is made half by using low resistance $R$. in shunt/parallel

$D$. High resistance box $S$. current per unit deflection

$T$. deflection per unit current

List-$I$	List-$II$
$A$. Figure of merit $(k)$	$P$. in series
$B$. Current sensitivity $(SI)$	$Q$. to get power loss minimized
$C$. Deflection is made half by using low resistance	$R$. in shunt/parallel
$D$. High resistance box	$S$. current per unit deflection
	$T$. deflection per unit current

Medium

View Solution

$A$ voltmeter of resistance $1000\,\Omega$ gives full scale deflection when a current of $100\,mA$ flows through it. The shunt resistance required across it to enable it to be used as an ammeter reading $1\,A$ at full scale deflection is ............... $\Omega$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

The coil of a moving coil galvanometer has an effective area of $4 \times 10^{-2} \, m^2$. It is suspended in a magnetic field of $5 \times 10^{-2} \, Wb \, m^{-2}$. If the deflection in the galvanometer coil is $0.2 \, rad$, when a current of $5 \, mA$ is passed through it, then

$A$ galvanometer has a resistance of $25 \, \Omega$ and a maximum of $0.01 \, A$ current can be passed through it. In order to change it into an ammeter of range $10 \, A$, the shunt resistance required is

$A$ voltmeter of resistance $1000\,\Omega$ gives full scale deflection when a current of $100\,mA$ flows through it. The shunt resistance required across it to enable it to be used as an ammeter reading $1\,A$ at full scale deflection is ............... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module