P is a point on the side BC of the Delta ABC | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that $\overrightarrow{PQ} = \overrightarrow{AP} + \overrightarrow{PB} + \overrightarrow{PC}$.By the triangle law of vector addition,$\overri

Vedclass · Accepted Answer

Parallelogram

Vedclass · Answer

(C) Given that $\overrightarrow{PQ} = \overrightarrow{AP} + \overrightarrow{PB} + \overrightarrow{PC}$.By the triangle law of vector addition,$\overrightarrow{AP} + \overrightarrow{PB} = \overrightarrow{AB}$.Substituting this into the given equation,we get $\overrightarrow{AB} + \overrightarrow{PC} = \overrightarrow{PQ}$.Rearranging the terms,we have $\overrightarrow{AB} = \overrightarrow{PQ} - \overrightarrow{PC}$.Since $\overrightarrow{PQ} - \overrightarrow{PC} = \overrightarrow{PQ} + \overrightarrow{CP} = \overrightarrow{CQ}$,we get $\overrightarrow{AB} = \overrightarrow{CQ}$.Since one pair of opposite sides is equal and parallel $(\overrightarrow{AB} = \overrightarrow{CQ})$,the quadrilateral $ABQC$ is a parallelogram.

$P$ is a point on the side $BC$ of the $\Delta ABC$ and $Q$ is a point such that $\overrightarrow{PQ}$ is the resultant of $\overrightarrow{AP}, \overrightarrow{PB}, \overrightarrow{PC}$. Then $ABQC$ is a

Similar Questions

$A$ vector coplanar with the non-collinear vectors $\vec{a}$ and $\vec{b}$ is:

In the given figure,which of the vectors are equal?

If the length of a vector is $21$ and its direction ratios are $2, -3, 6$,then its direction cosines are:

The vectors $a = 2\hat{i} + 3\hat{j} + 6\hat{k}$ and $b$ are collinear and $|b| = 21$,then $b =$

If $\overline{a} = m \overline{b} + n \overline{c}$,where $\overline{a} = 4 \hat{i} + 13 \hat{j} - 18 \hat{k}$,$\overline{b} = \hat{i} - 2 \hat{j} + 3 \hat{k}$,and $\overline{c} = 2 \hat{i} + 3 \hat{j} - 4 \hat{k}$,then $m + n =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module