sin 120^{circ} cos 150^{circ} - cos 240^{circ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We use the values of trigonometric functions for allied angles:$\sin 120^{\circ} = \sin(180^{\circ} - 60^{\circ}) = \sin 60^{\circ} = \frac{\sqrt{

Vedclass · Accepted Answer

$-1$

Vedclass · Answer

(B) We use the values of trigonometric functions for allied angles:$\sin 120^{\circ} = \sin(180^{\circ} - 60^{\circ}) = \sin 60^{\circ} = \frac{\sqrt{3}}{2}$$\cos 150^{\circ} = \cos(180^{\circ} - 30^{\circ}) = -\cos 30^{\circ} = -\frac{\sqrt{3}}{2}$$\cos 240^{\circ} = \cos(180^{\circ} + 60^{\circ}) = -\cos 60^{\circ} = -\frac{1}{2}$$\sin 330^{\circ} = \sin(360^{\circ} - 30^{\circ}) = -\sin 30^{\circ} = -\frac{1}{2}$Substituting these values into the expression:$\left(\frac{\sqrt{3}}{2}\right) \left(-\frac{\sqrt{3}}{2}\right) - \left(-\frac{1}{2}\right) \left(-\frac{1}{2}\right)$$= -\frac{3}{4} - \frac{1}{4}$$= -\frac{4}{4} = -1$

$\sin 120^{\circ} \cos 150^{\circ} - \cos 240^{\circ} \sin 330^{\circ}$ is equal to :

Similar Questions

Which of the following characteristics is $NOT$ applicable to algae?

In terms of period and group,where would you locate the element with $Z=114$?

Haemocoel is found in

Which of the following compound$(s)$ has '$Z$' configuration?

The ratio of rates of diffusion of gases $X$ and $Y$ is $1:5$ and that of $Y$ and $Z$ is $1:6$. The ratio of rates of diffusion of $Z$ and $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module