$\sin 20^{\circ} \cdot \sin 40^{\circ} \cdot \sin 60^{\circ} \cdot \sin 80^{\circ}$ is equal to

  • A
    $\frac{-3}{16}$
  • B
    $\frac{5}{16}$
  • C
    $\frac{3}{16}$
  • D
    $\frac{-5}{16}$

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