4-Nitrotoluene (para-nitrotoluene) on reducti | vedclass

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(C) $1$. The reduction of $4-$nitrotoluene with $Fe / HCl$ yields $4-$methylaniline ($p-$toluidine).$2$. The $-NH_2$ group is a strongly activating an

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$2,6-$dibromo$-4-$methylaniline

Vedclass · Answer

(C) $1$. The reduction of $4-$nitrotoluene with $Fe / HCl$ yields $4-$methylaniline ($p-$toluidine).$2$. The $-NH_2$ group is a strongly activating and $ortho-para$ directing group.$3$. The $-CH_3$ group is also an activating and $ortho-para$ directing group.$4$. In $4-$methylaniline,the $ortho$ positions relative to the $-NH_2$ group are the $2$ and $6$ positions.$5$. Since the $para$ position is already occupied by the $-CH_3$ group,electrophilic bromination with an excess of $Br_2$ occurs at both available $ortho$ positions ($2$ and $6$) relative to the $-NH_2$ group,resulting in $2,6-$dibromo-$4-$methylaniline.

$4-$Nitrotoluene ($para-$nitrotoluene) on reduction with $Fe / HCl$ and then electrophilic bromination with an excess amount of $Br_2$ gives

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