$f$ is a real-valued function satisfying the relation $f\left(3x + \frac{1}{2x}\right) = 9x^2 + \frac{1}{4x^2}$. If $f\left(x + \frac{1}{x}\right) = 1$, then $x =$

  • A
    $\pm 2$
  • B
    $\pm 1$
  • C
    $\pm 3$
  • D
    $\pm 6$

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