$y=\log \left\{\left(\frac{1+x}{1-x}\right)^{1 / 4}\right\}-\frac{1}{2} \tan ^{-1}(x)$, then $\frac{d y}{d x}$ is equal to

  • A
    $\frac{x}{1-x^2}$
  • B
    $\frac{x^2}{1-x^4}$
  • C
    $\frac{x}{1+x^4}$
  • D
    $\frac{x}{1-x^4}$

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