A square loop of side 'a' carrying a current | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic force on a current-carrying wire is given by $\vec{F} = I(\vec{L} 	imes \vec{B})$.For the bottom side of the loop of length '$a$',th

Vedclass · Accepted Answer

$2IaB$

Vedclass · Answer

(B) The magnetic force on a current-carrying wire is given by $\vec{F} = I(\vec{L} 	imes \vec{B})$.For the bottom side of the loop of length '$a$',the magnetic force is $F = IaB$.According to Fleming's Left-Hand Rule, if the current flows from left to right, the force is directed upwards. If the current flows from right to left, the force is directed downwards.Let the initial reading of the spring balance be $W_1 = mg - F$ (assuming upward force).When the current direction is reversed, the force becomes $F' = -F$ (downward force).The new reading of the spring balance becomes $W_2 = mg + F$.The change in the reading of the spring balance is $\Delta W = |W_2 - W_1| = |(mg + F) - (mg - F)| = 2F = 2IaB$.

Similar Questions

$A$ long straight wire carrying a current of $25 \ A$ rests on a table as shown in the figure. Another wire $PQ$ of length $1 \ m$ and mass $2.5 \ g$ carries the same current but in the opposite direction. The wire $PQ$ is free to slide up and down. To what height $h$ will $PQ$ rise?

What is the net force on the rectangular coil?

$A$ conducting circular loop of radius $r$ carries a constant current $i$. It is placed in a uniform magnetic field $B$,such that $B$ is perpendicular to the plane of the loop. The net magnetic force acting on the loop is

The force acting per unit length on a very long straight conductor carrying a steady current of $1 \,A$ flowing from south to north is: (The horizontal component of the earth's magnetic field at the place is $3 \times 10^{-5} \,T$ and its direction is from geographical south to geographical north.)

Vedclass Test Series

Exam Paper Generator

Online Exam Module