A conducting rod is moving towards the right | vedclass

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(C) The force on a charge '$q$' moving with velocity '$V$' in a magnetic field '$B$' is given by the Lorentz force formula: $\vec{F} = q(\vec{V} 	ime

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perpendicular to the plane of the paper and into the paper

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(C) The force on a charge '$q$' moving with velocity '$V$' in a magnetic field '$B$' is given by the Lorentz force formula: $\vec{F} = q(\vec{V} 	imes \vec{B})$.For a conducting rod, the positive charge carriers (holes) experience a force in the direction of the induced current '$i$'.In the given figure, the velocity '$V$' is towards the right and the current '$i$' is upwards.Using the right-hand rule for the cross product $\vec{V} 	imes \vec{B}$:If we point our fingers in the direction of '$V$' (right) and curl them towards the direction of '$B$' (into the paper), the thumb points upwards, which is the direction of the current '$i$'.Therefore, the magnetic field '$B$' must be perpendicular to the plane of the paper and directed into the paper.

$A$ conducting rod is moving towards the right with a velocity '$V$' in a uniform magnetic field '$B$'. If the direction of the induced current '$i$' is as shown in the figure, then the direction of '$B$' is:

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