A plane x passes through the point (1, 1, 1). | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First, we find the prime factors of $2001$. $2001 = 3 	imes 23 	imes 29$. Given that $a, b, c$ are the factors such that $a < b < c$, we have $a

Vedclass · Accepted Answer

$23x + 29y + 3z = 55$

Vedclass · Answer

(C) First, we find the prime factors of $2001$. $2001 = 3 	imes 23 	imes 29$. Given that $a, b, c$ are the factors such that $a The direction ratios of the normal to the plane are given as $b, c, a$, which are $23, 29, 3$. The equation of the plane is $bx + cy + az + d = 0$, which becomes $23x + 29y + 3z + d = 0$. Since the plane passes through the point $(1, 1, 1)$, we substitute these coordinates into the equation: $23(1) + 29(1) + 3(1) + d = 0$ $23 + 29 + 3 + d = 0$ $55 + d = 0$ $d = -55$. Thus, the equation of the plane is $23x + 29y + 3z - 55 = 0$, or $23x + 29y + 3z = 55$.

$A$ plane $x$ passes through the point $(1, 1, 1)$. If $b, c, a$ are the direction ratios of a normal to the plane, where $a, b, c$ $(a < b < c)$ are the factors of $2001$, then the equation of the plane is

Similar Questions

$Saccharomyces\, cerevisiae$ is used in the production of......

Identify the figure with its correct function.

Assign $A, B, C, D$ from the given type of reaction.
$P_4 + 6Cl_2 \xrightarrow{\Delta} 4PCl_3$

If $A=\begin{bmatrix} 1 & -2 \\ 4 & 5 \end{bmatrix}$ and $f(t)=t^2-3t+7$,then $f(A)+\begin{bmatrix} 3 & 6 \\ -12 & -9 \end{bmatrix}$ is equal to

If the vectors $a \hat{i}+\hat{j}+\hat{k}$,$\hat{i}+b \hat{j}+\hat{k}$,and $\hat{i}+\hat{j}+c \hat{k}$ $(a \neq 1, b \neq 1, c \neq 1, a \neq b \neq c)$ are coplanar,then the value of $\frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module