A bag contains 3 red, 5 black and 7 blue ball | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of balls = $3 + 5 + 7 = 15$. Number of ways to draw $3$ balls from $15$ is $^{15}C_3 = \frac{15 	imes 14 	imes 13}{3 	imes 2 	ime

Vedclass · Accepted Answer

$\frac{29}{65}$

Vedclass · Answer

(A) Total number of balls = $3 + 5 + 7 = 15$. Number of ways to draw $3$ balls from $15$ is $^{15}C_3 = \frac{15 	imes 14 	imes 13}{3 	imes 2 	imes 1} = 455$. We need to find the probability of getting at least two blue balls. This can happen in two cases: Case $1$: Exactly $2$ blue balls and $1$ non-blue ball. Number of ways = $^7C_2 	imes ^8C_1 = 21 	imes 8 = 168$. Case $2$: Exactly $3$ blue balls. Number of ways = $^7C_3 = \frac{7 	imes 6 	imes 5}{3 	imes 2 	imes 1} = 35$. Total favorable outcomes = $168 + 35 = 203$. Probability = $\frac{203}{455} = \frac{29 	imes 7}{65 	imes 7} = \frac{29}{65}$.

$A$ bag contains $3$ red, $5$ black and $7$ blue balls. If three balls are drawn at random simultaneously from the bag, then the probability of getting at least two blue balls is

Similar Questions

$A$ bag contains $6$ white and $4$ black balls. Two balls are drawn at random. The probability that they are of the same colour is . . . . . .

If the letters of the word "$ASSASSINATION$" are arranged at random in a row,then the probability that no two $A$'s come together is equal to

Three numbers are chosen at random from numbers $1$ to $20$. The probability that they are consecutive is

Four cards are drawn one by one from a well-shuffled pack of $52$ cards. What is the probability that all four cards belong to the same suit?

If $3$ dice are thrown, the probability of getting $10$ as the sum of the three numbers that appeared on the top faces of the dice is

Vedclass Test Series

Exam Paper Generator

Online Exam Module