A bag contains 6 white and 4 black balls. Two | vedclass

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(D) Total number of ways to select $2$ balls out of $10$ is given by $^{10}C_2 = \frac{10 	imes 9}{2 	imes 1} = 45$. Number of ways to select $2$ wh

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$7/15$

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(D) Total number of ways to select $2$ balls out of $10$ is given by $^{10}C_2 = \frac{10 	imes 9}{2 	imes 1} = 45$. Number of ways to select $2$ white balls from $6$ is $^{6}C_2 = \frac{6 	imes 5}{2 	imes 1} = 15$. Number of ways to select $2$ black balls from $4$ is $^{4}C_2 = \frac{4 	imes 3}{2 	imes 1} = 6$. Since the events are mutually exclusive, the number of favorable outcomes is $15 + 6 = 21$. Therefore, the required probability is $\frac{21}{45} = \frac{7}{15}$.

$A$ bag contains $6$ white and $4$ black balls. Two balls are drawn at random. The probability that they are of the same colour is

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