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(D) Given: Diameter of pipe $d = 5 \,mm = 5 	imes 10^{-3} \,m$. Density of gasoline $ho = 720 \,kg/m^3$. Viscosity of gasoline $\eta = 6 	imes 10^

Vedclass · Accepted Answer

$ > 0.33 \,m/s$

Vedclass · Answer

(D) Given: Diameter of pipe $d = 5 \,mm = 5 	imes 10^{-3} \,m$. Density of gasoline $ho = 720 \,kg/m^3$. Viscosity of gasoline $\eta = 6 	imes 10^{-3} \,Poise = 6 	imes 10^{-4} \,Pa \cdot s$. The critical Reynolds number for pipe flow is $R_e = 2000$. The formula for critical velocity $v_c$ is $v_c = \frac{R_e \cdot \eta}{ho \cdot d}$. Substituting the values: $v_c = \frac{2000 	imes 6 	imes 10^{-4}}{720 	imes 5 	imes 10^{-3}} = \frac{1.2}{3.6} = \frac{1}{3} \approx 0.33 \,m/s$. Thus, the flow becomes turbulent when the velocity is $ > 0.33 \,m/s$.

$A$ horizontal pipeline carrying gasoline has a cross-sectional diameter of $5 \,mm$. If the viscosity and density of the gasoline are $6 \times 10^{-3} \,Poise$ and $720 \,kg/m^3$ respectively, the velocity after which the flow becomes turbulent is:

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