A heavy nucleus at rest breaks into two fragm | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the law of conservation of linear momentum, for a nucleus initially at rest, the magnitudes of momenta of the two fragments must be e

Vedclass · Accepted Answer

$1: 3^{1/3}$

Vedclass · Answer

(A) According to the law of conservation of linear momentum, for a nucleus initially at rest, the magnitudes of momenta of the two fragments must be equal: $m_1 v_1 = m_2 v_2$. This implies $\frac{m_1}{m_2} = \frac{v_2}{v_1}$. Given the velocity ratio $\frac{v_1}{v_2} = \frac{3}{1}$, we have $\frac{m_1}{m_2} = \frac{1}{3}$. Assuming the density $\rho$ of the nucleus is constant, the mass $m$ is proportional to the volume, so $m = \rho \cdot \frac{4}{3} \pi R^3$. Therefore, $\frac{m_1}{m_2} = \frac{R_1^3}{R_2^3}$. Equating the two expressions for the mass ratio: $\frac{R_1^3}{R_2^3} = \frac{v_2}{v_1} = \frac{1}{3}$. Taking the cube root on both sides, we get $\frac{R_1}{R_2} = (\frac{1}{3})^{1/3} = 1 : 3^{1/3}$.

$A$ heavy nucleus at rest breaks into two fragments which fly off with velocities in the ratio $3: 1$. The ratio of radii of the fragments is

Similar Questions

Assume that a neutron breaks into a proton and an electron. The energy released during this process is: ............ $MeV$ (mass of neutron $= 1.6725 \times 10^{-27} \ kg$,mass of proton $= 1.6725 \times 10^{-27} \ kg$,mass of electron $= 9 \times 10^{-31} \ kg$).

Weak nuclear force always operates between

If the nuclear radius of ${}_{13}^{27}Al$ is $3.6 \, fm$,the approximate nuclear radius of ${}_{29}^{64}Cu$ in fermi is .......... $fm$.

In the nuclear reaction: $X(n, \alpha) {_3Li^7}$,the term $X$ will be

Give one example each of central force and non-central force.

Vedclass Test Series

Exam Paper Generator

Online Exam Module