(C) For dispersion without deviation through a prism combination, the net deviation must be zero.$\delta_{net} = \delta_1 - \delta_2 = 0$$\Rightarrow

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(C) For dispersion without deviation through a prism combination, the net deviation must be zero.$\delta_{net} = \delta_1 - \delta_2 = 0$$\Rightarrow \delta_1 = \delta_2$For thin prisms, the deviation is given by $\delta = A(\mu - 1)$.Therefore, $A_1(\mu_1 - 1) = A_2(\mu_2 - 1)$.Given: $A_1 = 9^{\circ}$, $\mu_1 = 1.4$, and $\mu_2 = 1.6$.Substituting the values:$9^{\circ} \times (1.4 - 1) = A \times (1.6 - 1)$$9^{\circ} \times 0.4 = A \times 0.6$$A = \frac{9 \times 0.4}{0.6} = \frac{3.6}{0.6} = 6^{\circ}$.

Class 12 Physics Ray Optics and Optical Instruments Refraction Through Prism

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$A$ thin glass prism of angle $9^{\circ}$ with refractive index $1.4$ is combined with another glass prism of refractive index $1.6$ as shown in the figure. The combination of the prisms provides dispersion without deviation. Determine the angle $(A)$ of the second prism. (in $^{\circ}$)

TS EAMCET 2020 All TS EAMCET

A
$9$
B
$12$
C
$6$
D
$4$

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Ray Optics and Optical Instruments

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$A$ thin glass prism of angle $9^{\circ}$ with refractive index $1.4$ is combined with another glass prism of refractive index $1.6$ as shown in the figure. The combination of the prisms provides dispersion without deviation. Determine the angle $(A)$ of the second prism. (in $^{\circ}$)

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