$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

The current amplification factor and the collector current in a $CE$ transistor circuit are $100$ and $2.2 \text{ mA}$ respectively. Then the base current is (in $\mu A$)

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.

The transfer ratio of a transistor is $50$. The input resistance of the transistor when used in the common-emitter configuration is $1 \; k\Omega$. The peak value of the collector current for an $A.C.$ input voltage of $0.01 \; V$ peak is:

$A$ transistor oscillator is a device that is used to: