$A$ hydrogen atom in the ground state absorbs $\Delta E$ amount of energy. If the orbital angular momentum of the electron is increased by $\frac{h}{2 \pi}$ ($h=$ Planck constant), then the magnitude of $\Delta E$ is (in $eV$)

  • A
    $12.09$
  • B
    $12.75$
  • C
    $10.2$
  • D
    $13.6$

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