$A$ metal wire of circular cross-section has a resistance $R_{1}$. The wire is now stretched without breaking, so that its length is doubled and the density is assumed to remain the same. If the resistance of the wire now becomes $R_{2}$, then $R_{2}: R_{1}$ is

  • A
    $1: 1$
  • B
    $1: 2$
  • C
    $4: 1$
  • D
    $1: 4$

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