A neutral conducting solid sphere of radius R | vedclass

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(C) When a charge $q_a$ is placed inside a cavity of a conducting sphere, it induces a charge $-q_a$ on the inner surface of the cavity and a charge $

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zero

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(C) When a charge $q_a$ is placed inside a cavity of a conducting sphere, it induces a charge $-q_a$ on the inner surface of the cavity and a charge $+q_a$ on the outer surface of the conducting sphere.Similarly, placing $q_b$ in the other cavity induces $-q_b$ on its inner surface and $+q_b$ on the outer surface of the conducting sphere.The total charge on the outer surface of the conducting sphere becomes $q_a + q_b$. Since the sphere is conducting, the electric field inside the bulk of the conductor is zero.The charge $q_a$ experiences a force due to the field produced by the induced charge $-q_b$ on the inner surface of the second cavity and the field produced by the charge distribution on the outer surface of the sphere.However, due to the electrostatic shielding property of the conductor, the electric field produced by the charges outside the cavity (including the outer surface charge and the other cavity's induced charge) is zero inside the cavity containing $q_a$.Therefore, the charge $q_a$ only experiences the field produced by the charge $-q_b$ induced on the inner surface of its own cavity, which is zero at its center due to symmetry.Thus, the net force on $q_a$ due to $q_b$ and the induced charges is zero.

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