$\mathop {\lim }\limits_{x \to 0} \frac{{\sin ax}}{{\sin bx}} = $

  • A
    $a/b$
  • B
    $b/a$
  • C
    $1$
  • D
    None of these

Explore More

Similar Questions

The value of $\lim_{x \to 0} (\cos ax)^{\csc^2 bx}$ is

$\lim _{x \rightarrow 0^{-}} \frac{\sqrt{\frac{1}{2}(1-\cos ^2 x)}}{x}$ is equal to

$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos 2x}}{x} = $

$\lim _{x \rightarrow \pi} \frac{1-\sin (x/2)}{\left(\cos \frac{x}{2}\right)\left(\cos \frac{x}{4}-\sin \frac{x}{4}\right)} =$

$\lim _{x \rightarrow 0} \frac{x \tan 2 x-2 x \tan x}{(1-\cos 3 x)(\operatorname{cosec} x-\cot x)^2}=$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo