mathop {lim }limits_{x to 0} left( frac{x}{ta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $	an^{-1} 2x = 	heta$. Then $2x = 	an 	heta$,which implies $x = \frac{1}{2} 	an 	heta$. As $x 	o 0$,$	heta 	o 0$. Substituting these

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(B) Let $	an^{-1} 2x = 	heta$. Then $2x = 	an 	heta$,which implies $x = \frac{1}{2} 	an 	heta$. As $x 	o 0$,$	heta 	o 0$. Substituting these into the limit: $\mathop {\lim }\limits_{x 	o 0} \frac{x}{	an^{-1} 2x} = \mathop {\lim }\limits_{	heta 	o 0} \frac{\frac{1}{2} 	an 	heta}{	heta} = \frac{1}{2} \mathop {\lim }\limits_{	heta 	o 0} \frac{	an 	heta}{	heta}$. Since $\mathop {\lim }\limits_{	heta 	o 0} \frac{	an 	heta}{	heta} = 1$,the result is $\frac{1}{2} 	imes 1 = \frac{1}{2}$.

$\mathop {\lim }\limits_{x \to 0} \left( \frac{x}{\tan^{-1} 2x} \right) = $

Similar Questions

$\mathop {\lim }\limits_{x \to \frac{\pi^+}{2}} e^{[\cot x]}$ is equal to :-
(where $[.]$ is the greatest integer function)

The value of $\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {1 - \cos {x^2}} }}{{1 - \cos x}}$ is

If $\mathop {\lim }\limits_{x \to 5} \frac{{{x^k} - {5^k}}}{{x - 5}} = 500$,then the positive integral value of $k$ is

$\lim _{x \rightarrow 0} \frac{1-\cos \left(x^2+\pi(x+2)\right)}{x^2} = $

Evaluate the given limit: $\mathop {\lim }\limits_{x \to 0} \frac{\cos x}{\pi - x}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module