mathop {lim }limits_{x to 0} frac{{3sin x - s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) આપણે જાણીએ છીએ કે ત્રિકોણમિતીય નિત્યસમ $\sin 3x = 3\sin x - 4\sin^3 x$ છે. આ કિંમત પદાવલિમાં મૂકતા: $\mathop {\lim }\limits_{x 	o 0} \frac{{3\sin

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) આપણે જાણીએ છીએ કે ત્રિકોણમિતીય નિત્યસમ $\sin 3x = 3\sin x - 4\sin^3 x$ છે. આ કિંમત પદાવલિમાં મૂકતા: $\mathop {\lim }\limits_{x 	o 0} \frac{{3\sin x - (3\sin x - 4\sin^3 x)}}{{{x^3}}}$ $= \mathop {\lim }\limits_{x 	o 0} \frac{{4\sin^3 x}}{{{x^3}}}$ $= 4 	imes \mathop {\lim }\limits_{x 	o 0} \left( \frac{\sin x}{x} ight)^3$ કારણ કે $\mathop {\lim }\limits_{x 	o 0} \frac{\sin x}{x} = 1$,તેથી આપણને મળે છે: $= 4 	imes (1)^3 = 4$.

$\mathop {\lim }\limits_{x \to 0} \frac{{3\sin x - \sin 3x}}{{{x^3}}} = $

Similar Questions

$\mathop {\lim }\limits_{\theta \to 0} \frac{{1 - \cos \theta }}{{{\theta ^2}}} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin (\pi {{\cos }^2}x)}}{{{x^2}}} = $

$\lim _{x \rightarrow 0} \left( \frac{\sin (\pi \cos ^2 x)}{x^2} \right) = $

$\lim _{x \rightarrow 0} \frac{(1-\cos 2 x)}{x \tan 2 x+\frac{2 x}{3} \tan 3 x} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin 2x + \sin 6x}}{{\sin 5x - \sin 3x}} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module