(B) The angular width of the central maximum in a single slit diffraction pattern is given by $\theta = \frac{2\lambda}{a}$, where $\lambda$ is the wa

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fringes will become narrower and crowded together

(B) The angular width of the central maximum in a single slit diffraction pattern is given by $\theta = \frac{2\lambda}{a}$, where $\lambda$ is the wavelength of light and $a$ is the slit width.Since the wavelength of blue light $(\lambda_{blue})$ is smaller than the wavelength of red light $(\lambda_{red})$, the angular width of the diffraction fringes decreases.Therefore, the fringes become narrower and more crowded together.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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$A$ single slit diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light, then:

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A
the diffraction pattern will disappear
B
fringes will become narrower and crowded together
C
fringes will become broader and will be further apart
D
there is no change in the diffraction pattern

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Wave Optics

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Single Slit Diffraction of Light

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Light of wavelength $6000 \, \mathring A$ is incident on a slit of width $0.30 \, mm$. $A$ screen is placed at a distance of $2 \, m$ from the slit. Find the position of the first minimum.

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In the case of Fraunhofer diffraction due to a single slit,the intensity of the central maximum is $I_0$. If the width of the slit is doubled,what will be the new intensity of the central maximum?

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In a diffraction pattern due to a single slit of width $a$,the first minimum is observed at an angle $30^{\circ}$ when light of wavelength $5000 \; \mathring{A}$ is incident on the slit. The first secondary maximum is observed at an angle of

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In a diffraction pattern produced by a thin wire,what happens to the fringe width when the diameter of the wire is increased?

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In a diffraction pattern, light of wavelength $580 \,nm$ is incident normally on a slit of width '$a$'. The distance between the slit and the screen is $2.5 \,m$ and the distance of the second-order maximum from the center of the screen is $14.5 \,mm$. The value of '$a$' is:

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$A$ single slit diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light, then:

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Light of wavelength $6000 \, \mathring A$ is incident on a slit of width $0.30 \, mm$. $A$ screen is placed at a distance of $2 \, m$ from the slit. Find the position of the first minimum.

In the case of Fraunhofer diffraction due to a single slit,the intensity of the central maximum is $I_0$. If the width of the slit is doubled,what will be the new intensity of the central maximum?

In a diffraction pattern due to a single slit of width $a$,the first minimum is observed at an angle $30^{\circ}$ when light of wavelength $5000 \; \mathring{A}$ is incident on the slit. The first secondary maximum is observed at an angle of

In a diffraction pattern produced by a thin wire,what happens to the fringe width when the diameter of the wire is increased?

In a diffraction pattern, light of wavelength $580 \,nm$ is incident normally on a slit of width '$a$'. The distance between the slit and the screen is $2.5 \,m$ and the distance of the second-order maximum from the center of the screen is $14.5 \,mm$. The value of '$a$' is:

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