$\mathop {\lim }\limits_{x \to \infty } (\sqrt {{x^2} + 8x + 3} - \sqrt {{x^2} + 4x + 3} ) = $

  • A
    $0$
  • B
    $\infty $
  • C
    $2$
  • D
    $\frac{1}{2}$

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