$A$ moving coil galvanometer of resistance $100 \ \Omega$ shows a full scale deflection for a current of $1 \ mA$. The value of shunt resistance required to convert this galvanometer into an ammeter, showing full scale deflection for a current of $5 \ mA$, is . . . . . . $\Omega$.

Two moving coil galvanometers $A$ and $B$ having identical springs are placed in magnetic fields of $0.25 \ T$ and $0.5 \ T$ respectively. If the number of turns in $A$ and $B$ are respectively $36$ and $48$,and the areas of the coils $A$ and $B$ are $2.4 \times 10^{-3} \ m^2$ and $4.8 \times 10^{-3} \ m^2$ respectively,then the ratio of the current sensitivities of the galvanometers $A$ and $B$ is

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

$A$ galvanometer coil of resistance $50 \,\Omega$ shows full-scale deflection for a current of $100 \,\mu A$. The shunt resistance to be added to the galvanometer to convert it into an ammeter of range $10 \, mA$ is:

The net resistance of a voltmeter should be large to ensure that

If an ammeter is to be used in place of a galvanometer,then we must connect: